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Question

Physics Question on Waves

A string of length \ell is fixed at both ends. It is vibrating in its 3rd3^{rd} overtone with maximum amplitude 'aa'. The amplitude at a distance /3\ell /3 from one end is.

A

a

B

0

C

3a2\frac{\sqrt{3a}}{2}

D

a2\frac {a}{2}

Answer

3a2\frac{\sqrt{3a}}{2}

Explanation

Solution

For a string vibrating in its nth n^{\text {th }} overtone (n+1)th (n+1)^{\text {th }} harmonic) y=2Asin((n+1)πxL)cosωty=2 A \sin \left(\frac{(n+1) \pi x}{L}\right) \cos \omega t Fox x=3]2A=a&n=3\left.x=\frac{\ell}{3}\right] 2 A=a\, \& \,n=3; y=[asin(4π3)]cosωty=\left[a \sin \left(\frac{4 \pi}{\ell} \cdot \frac{\ell}{3}\right)\right] \cos \omega t =asin4π3cosωt=a(32)cosωt=a \sin \frac{4 \pi}{3} \cos \omega t=-a\left(\frac{\sqrt{3}}{2}\right) \cos \omega t i.e. at x=3x=\frac{\ell}{3}, the amplitude is 3a2\frac{\sqrt{3 a}}{2}