Question

A string is producing transverse vibration whose equation is $y = 0.021\mspace{6mu}\sin(x + 30t)$, Where x and y are in meters and $t$ is in seconds. If the linear density of the string is $1.3 \times 10^{- 4}$kg/m, then the tension in the string in $N$ will be

• A. 10
• B. 0.5
• C. 1
• D. 0.117

Answer 1

Answer: (D)

0.117

Answer 2

$y = 0.021\sin(x + 30t)$ ⇒ $v = \frac{\omega}{k} = \frac{30}{1} = 30m/s$.

Using, $v = \sqrt{\frac{T}{m}} \Rightarrow 30 = \sqrt{\frac{T}{1.3 \times 10^{- 4}}} \Rightarrow T = 0.117$N