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Question

Physics Question on Waves

A string in a musical instrument is 50cm50\, cm long and its fundamental frequency is 800Hz800\, Hz. If a frequency of 1000Hz1000\, Hz is to be produced, then required length of string is

A

62.5 cm

B

40 cm

C

50 cm

D

37.5 cm

Answer

40 cm

Explanation

Solution

Fundamental frequency υ=12LTμ\upsilon = \frac{1}{2L} \sqrt{\frac{T}{\mu}}
υ1L8001000=L50\upsilon \propto \frac{1}{L} \, \therefore \frac{800}{1000} = \frac{L'}{50}
L=800×501000=40cmL' = \frac{800 \times 50}{1000} = 40 \, cm