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Question

Physics Question on Waves

A stretched string of length ll, fixed at both ends, can sustain Stationary waves of wavelength of wavelength λ,\lambda, correctly given by

A

λ=l22p\lambda=\frac{l^2}{2p}

B

λ=p22l\lambda=\frac{p^2}{2l}

C

λ=2lp\lambda=2lp

D

λ=2lp\lambda=\frac{2l}{p}

Answer

λ=2lp\lambda=\frac{2l}{p}

Explanation

Solution

If the string has a length ll and both ends are fixed then only vibrational modes are allowed where an integer number of half-wavelengths equals the string length. Now the fundamental wavelength in the wire is: λ=2lp\lambda=\frac{2 l }{ p } where, p=1,2,3..p =1,2,3 . .