Question: A stretched string of 1m length and mass $5 \times 10^{- 4}kg$ is having tension of 20N. If it is ...

Question

A stretched string of 1m length and mass $5 \times 10^{- 4}kg$ is having tension of 20N. If it is plucked at 25cm from one end then it will vibrate with frequency

Answer 1

Solution

As we know plucking distance from one end $= \frac{l}{2p}$

⇒ $25 = \frac{100}{2p}$ ⇒ $p = 2$ . Hence frequency of vibration

$n = \frac{p}{2l}\sqrt{\frac{T}{m}} = \frac{2}{2 \times 1}\sqrt{\frac{20}{5 \times 10^{- 4}}}$ = $200Hz.$

Question: A stretched string of 1m length and mass \(5 \times 10^{- 4}kg\) is having tension of 20N. If it is ...

Solution