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Question

Chemistry Question on Structure of atom

A stream of electrons from a heated filament was passed between two charged plates kept at a potential difference VV esu. If ee and mm are charge and mass of an electron, respectively, then the value of h/λh/ \lambda (where λ\lambda is wavelength associated with electron wave) is given by :

A

meVmeV

B

2meV2 meV

C

meV\sqrt{meV}

D

2meV\sqrt{ 2 meV}

Answer

2meV\sqrt{ 2 meV}

Explanation

Solution

λ=hP=h2mE=h2meV\lambda = \frac{h}{P} = \frac{h}{\sqrt{2mE}} = \frac{h}{\sqrt{2me\,V}}
hλ=2meV\Rightarrow \frac{h}{\lambda} = \sqrt{2me\,V}