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Physics Question on Moving charges and magnetism

A straight wire (conductor) of length 10 cm is kept in a uniform magnetic field of induction 0.02 T. The angle between the conductor and the-field direction is 30. A current of 5A is passed through the conductor. The force on the conductor is (in N)

A

4×10−34\times 10^{-3}

B

5×10−35\times 10^{-3}

C

6×10−36\times 10^{-3}

D

7×10−37\times 10^{-3}

Answer

5×10−35\times 10^{-3}

Explanation

Solution

F=Bil sin θF =Bil\,sin\,\theta