Solveeit Logo

Question

Question: A straight wire carrying current i is turned into a circular loop. If the magnitude of magnetic mome...

A straight wire carrying current i is turned into a circular loop. If the magnitude of magnetic moment associated with it in M.K.S. unit is M, the length of wire will be

A

4πiM4 \pi i M

B

4πMi\sqrt { \frac { 4 \pi M } { i } }

C

4πiM\sqrt { \frac { 4 \pi i } { M } }

D

Mπ4i\frac { M \pi } { 4 i }

Answer

4πMi\sqrt { \frac { 4 \pi M } { i } }

Explanation

Solution

Magnetic moment of circular loop carrying current

M=IA=I(πR2)=Iπ(L2π)2=IL24πL=4πMIM = I A = I \left( \pi R ^ { 2 } \right) = I \pi \left( \frac { L } { 2 \pi } \right) ^ { 2 } = \frac { I L ^ { 2 } } { 4 \pi } \Rightarrow L = \sqrt { \frac { 4 \pi M } { I } }