Question
Question: A straight vertical conductor carries a current. At a point \[5cm\] due north of it, the magnetic in...
A straight vertical conductor carries a current. At a point 5cm due north of it, the magnetic induction is found to be 20T due east. The magnitude of magnetic induction at a point 10cm east of it will be
A. 20T
B. 40T
C. 5T
D. 10T
Solution
The magnetic induction is inversely proportional to the distance. If the magnetic induction is high, the distance is less. The quantity of magnetic induction and the distance are inversely proportional.
Formula used:
Bαr1
To remove the proportionality constant, it gives an equation. This expression gives the magnitude of the magnetic field around the wire. The final equation is,
B=2πrμ0I
Where,
μ0- Permeability of free space, it has a constant value, μ0=4π×10−7Tm/A
B - Magnetic induction
r – distance between the conduction and measured point
Complete step by step solution:
B1 is the magnetic induction produced at the distance 5cm of north, here B1=20T, r1=5cm and B2 is the magnetic induction produced at the distance 10cm of east, r2=10cm.
B1=r11
B2=r21
B2B1=r1r2
Substitute the values in the above equation,
B220T=510
B2=10T
Hence the correct option is D.
Additional Information:
Magnetic induction was first discovered by Michael Faraday and published in 1831 . After that 1831 faraday shows an experimental demonstration to prove magnetic induction. Faraday explained the phenomenon of electromagnetic induction using the concept of lines of force. But all the scientists rejected his ideas at that time because they were not expressed and explained mathematically. But one scientist named James Clerk Maxwell used Faraday's ideas as the basis of his electromagnetic theory.
Note:
If the wire is not straight, or it’s a circular loop, the magnetic induction around the circular loop has a pattern similar to the bar magnet field lines. The loop has a radius R, the equation for the magnetic induction in a circular loop is,
B=2Rμ0I
If the loop consists of a N number of turns, then the equation for the magnetic induction will be written as,
B=N2Rμ0I