Question

A straight magnetic strip has a magnetic moment of $44 \, \text{A m}^2$. If the strip is bent in a semicircular shape, its magnetic moment will be $\dots$ A m$^2$. $\text{(Given } \pi = \frac{22}{7} \text{)}$

Answer 1

Given: The magnetic moment of the straight strip is $44 \, \mathrm{Am}^2$. The strip is bent into a semicircular shape.
When a straight magnetic strip is bent into a semicircular shape, the magnetic moment changes based on the geometry. The formula for the magnetic moment $M$ of a circular loop is given by:
$M = I \times A,$
where $I$ is the current and $A$ is the area of the loop. For a semicircular loop, the area is half of the area of a full circle.

The magnetic moment $M'$ after bending is:
$M' = \frac{M}{2}.$

So, the magnetic moment after bending the strip into a semicircular shape is:
$M' = \frac{44}{2} = 28 \, \mathrm{Am}^2.$
Thus, the correct answer is 28.

Answer 2

Given: The magnetic moment of the straight strip is $44 \, \mathrm{Am}^2$. The strip is bent into a semicircular shape.
When a straight magnetic strip is bent into a semicircular shape, the magnetic moment changes based on the geometry. The formula for the magnetic moment $M$ of a circular loop is given by:
$M = I \times A,$
where $I$ is the current and $A$ is the area of the loop. For a semicircular loop, the area is half of the area of a full circle.

The magnetic moment $M'$ after bending is:
$M' = \frac{M}{2}.$

So, the magnetic moment after bending the strip into a semicircular shape is:
$M' = \frac{44}{2} = 28 \, \mathrm{Am}^2.$
Thus, the correct answer is 28.