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Question: A straight line through the point \[A(3,4)\] is such that its intercept between the axes is bisected...

A straight line through the point A(3,4)A(3,4) is such that its intercept between the axes is bisected at A. it’s equation is-
A. 3x4y+7=03x - 4y + 7 = 0
B. 4x+3y=244x+ 3y = 24
C. 3x4y=253x - 4y = 25
D. xy=7x - y = 7

Explanation

Solution

Hint : In this question, the point A(3,4)A(3,4) which passes through the straight line. To find the equation of line, we use the slope-intercept formula. First we determine the end point of the straight line and evaluate by using the formula.

Complete step-by-step answer :
Here A(3,4)A(3,4) is a point which passes through the straight line. Consider BCBC is a straight-line having points (a,0)(a,0) and (0,b)(0,b) . Let AA be the midpoint of the line BCBC .

By using the midpoint formula, we determine the end points as

a+02=3 and 0+b2=4 a2=3 and b2=4   \dfrac{{a + 0}}{2} = 3{\text{ and }}\dfrac{{0 + b}}{2} = 4 \\\ \Rightarrow \dfrac{a}{2} = 3{\text{ and }}\dfrac{b}{2} = 4 \;

By simplifying, we have a=6a = 6 and b=8b = 8 .
Hence, we determined the endpoints. Now we have to find the equation of line.
To find the equation of line we consider the slope-intercept formula which is given by y=mx+by = mx + b . yy is yy coordinate, mm is slope, xx is xx coordinate and bb is yy intercept.
First we determine the slope mm is given by m=y2y1x2x1m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}} where (x1,y1)({x_1},{y_1}) and (x2,y2)({x_2},{y_2}) are the endpoints of the straight line. Here (x1,y1)({x_1},{y_1}) and (x2,y2)({x_2},{y_2}) are (6,0)(6,0) and (0,8)(0,8)

m=8006 =86=86   m = \dfrac{{8 - 0}}{{0 - 6}} \\\ = \dfrac{8}{{ - 6}} = - \dfrac{8}{6} \;

Therefore the equation of line by intercept formula is y=mx+by = mx + b
y=(86)x+8y = \left( { - \dfrac{8}{6}} \right)x + 8
By taking L.C.M.

y=8x+486 6y=8x+48   y = \dfrac{{ - 8x + 48}}{6} \\\ \Rightarrow 6y = - 8x + 48 \;

Dividing the above equation by 2 we have

3y=4x+24 4x+3y=24   3y = - 4x + 24 \\\ \Rightarrow 4x + 3y = 24 \;

∴ the equation of line is given by 4x+3y=244x + 3y = 24
So, the correct answer is “Option B”.

Note : To find the equation of a line we need the end points. In this question first, we have to determine the endpoints of the straight line. After determining the endpoints, we can determine the equation of the line by using the slope intercept formula. Here we considered the point A(3,4)A(3,4) as midpoint and we determined the end points and evaluated them using the slope intercept formula.