Question

A straight line through the point A (3, 4) is such that its intercept between the axes is bisected at A. Its equation is :

• A. $3x - 4y + 7 = 0$
• B. $4x + 3y = 24$
• C. $3x + 4y = 25$
• D. $x + y = 7$

Answer 1

Answer: (B)

$4x + 3y = 24$

Answer 2

Since A is midpoint of line $PQ$ $\therefore 3=\frac{a+0}{2} \Rightarrow a=6$ and $4=\frac{0+b}{2} \Rightarrow b=8$ Thus the equation of line is $\frac{x}{6}+\frac{y}{8}=1$ $\Rightarrow 4x+3y=24$