Question

A straight line L is perpendicular to the line

5x – y = 1. If the area of the triangle formed by the line L and the co-ordinate axis is 5 then the equation of line L is –

• A. x + 3y ± $3 \sqrt { 2 }$ = 0
• B. x + 2y ± $\sqrt { 2 }$ = 0
• C. x + 5y ± $5 \sqrt { 2 }$ = 0
• D. None of these

Answer 1

Answer: (C)

x + 5y ± $5 \sqrt { 2 }$ = 0

Answer 2

L = x + 5y + l = 0

$\frac { 5 y } { - \lambda }$ = 1 Ž + = 1

Ž area of D = $\frac { 1 } { 2 }$(– l)$\left( \frac { - \lambda } { 5 } \right)$

Ž 5 = $\sqrt { 50 }$ Ž l = ± $5 \sqrt { 2 }$