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Question

Physics Question on Electromagnetic induction

A straight line conductor of length 0.4 m is moved with a speed of 7 m/s perpendicular to a magnetic field of intensity 0.9 Wb/m2m^2. The induced e.m.f. across the conductor is

A

5.04 V

B

25.2 V

C

1.26V

D

2.52V.

Answer

2.52V.

Explanation

Solution

Length of conductor (I) = 0.4 m; Speed = 7 m/s and magnetic field (B) = 0.9 Wb/m2m^2. Induced e.m.f. ()=Blv=0.9×0.4×7=2.52V(\in)=Blv \, \, =0.9\times0.4\times7=2.52 V.