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Question

Physics Question on Inductance

A straight conductor 0.1m0.1\, m long moves in a uniform magnetic field 0.1T0.1\, T. The velocity of the conductor is 15m/s15\, m / s and is directed perpendicular to the field. The emf induced between the two ends of the conductor is

A

0.10 V

B

0.15 V

C

1.50 V

D

15.00 V

Answer

0.15 V

Explanation

Solution

Given, length of conductor l=0.1ml=0.1\, m
Mangetic field, B=0.1TB=0.1\, T
Velocity of conductor, v=15m/sv=15\, m / s
The angle between vv and BB is 9090^{\circ}
When vv and BB are mutually perpendicular, then emf (induced) is given by
ε=vBl=15×0.1×0.1\varepsilon=v B l=15 \times 0.1 \times 0.1
=15100=0.15V=\frac{15}{100}=0.15\, V