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Question

Physics Question on Motion in a straight line

A stone thrown vertically upwards with a speed of 5 m/sec attains a height H1H_1. Another stone thrown upwards from the same point with a speed of 10 m/sec attains a height H2H_2. The correct relation between H1H_1 and H2H_2 is

A

H2=4H1H_2 = 4 H_1

B

H2=3H1H_2 = 3 H_1

C

H1=2H2H_1 = 2 H_2

D

H1=H2H_1 = H_2

Answer

H2=4H1H_2 = 4 H_1

Explanation

Solution

From third equation of motion v2=u2+2ahv^2 = u^2 + 2ah In first case initial velocity u1=5m/secu_1 = 5 \, m/ \sec final velocity v1=0,a=gv_1 = 0, a = - g and max. height obtained is H1H_1, then, H1=252gH_1 = \frac{25}{2g} In second case u2=10m/sec,v2=0,a=gu_2 = 10 \, m/ \sec, v_2 = 0, a = -g and max. height is H2H_2 then, H2=1002gH_2 = \frac{100}{2g} It implies that H2=4H1H_2 = 4H_1