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Question: A stone of mass m is tied to a string and is moved in a vertical circle of radius r making n revolut...

A stone of mass m is tied to a string and is moved in a vertical circle of radius r making n revolutions per minute. The total tension in the string when the stone is at its lowest point is

A

m{g+(π2n2r)/900}m\{ g + (\pi^{2}n^{2}r)/900\}

B

m(g+πnr2)m(g + \pi nr^{2})

C

m(g+πnr)m(g + \pi nr)

D

m(g+n2r2)m(g + n^{2}r^{2})

Answer

m{g+(π2n2r)/900}m\{ g + (\pi^{2}n^{2}r)/900\}

Explanation

Solution

Tension at lowest point T=mg+mw2rT = mg + mw^{2}r

=mg+m4π2n2r= mg + m4\pi^{2}n^{2}r

If n is revolution per minute then T=mg+m4π2n23600r=mg+mπ2n2r900=m[g+π2n2r900]T = mg + m4\pi^{2}\frac{n^{2}}{3600}r = mg + \frac{m\pi^{2}n^{2}r}{900} = m\left\lbrack g + \frac{\pi^{2}n^{2}r}{900} \right\rbrack