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Question: A stone of mass 5 kg is tied to a string of length 10 m is whirled round in a horizontal circle. Wha...

A stone of mass 5 kg is tied to a string of length 10 m is whirled round in a horizontal circle. What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of 200 N?

A

10 m s110 \mathrm {~m} \mathrm {~s} ^ { - 1 }

B

15 m s115 \mathrm {~m} \mathrm {~s} ^ { - 1 }

C

20 m s120 \mathrm {~m} \mathrm {~s} ^ { - 1 }

D

25 m s125 \mathrm {~m} \mathrm {~s} ^ { - 1 }

Answer

20 m s120 \mathrm {~m} \mathrm {~s} ^ { - 1 }

Explanation

Solution

Here m=5 kg,r=10 m,Tmax=200 Nm = 5 \mathrm {~kg} , r = 10 \mathrm {~m} , T _ { \max } = 200 \mathrm {~N}

As Tmax=mvmax2rvmax2=Tmax×rmT _ { \max } = \frac { m v _ { \max } ^ { 2 } } { r } \therefore v _ { \max } ^ { 2 } = \frac { T _ { \max } \times r } { m }

vmax2=200×105=400vmax=20 ms1\therefore v _ { \max } ^ { 2 } = \frac { 200 \times 10 } { 5 } = 400 \Rightarrow v _ { \max } = 20 \mathrm {~ms} ^ { - 1 }