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Question: A stone of mass 1 kg tied to the end of a string of length 1 m, is whirled in a horizontal circle wi...

A stone of mass 1 kg tied to the end of a string of length 1 m, is whirled in a horizontal circle with a uniform angular velocity of 2 rad/s. The tension of the string is (in N)

A

2

B

13\frac{1}{3}

C

4

D

14\frac{1}{4}

Answer

4

Explanation

Solution

T=mω2r=1×(2)2×(1)=4NewtonT = m\omega^{2}r = 1 \times (2)^{2} \times (1) = 4Newton