Question
Physics Question on laws of motion
A stone of mass 0.05kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion ?
A
0.49 N vertically upwards
B
0.49 N vertically downwards
C
0.98 N vertically downwards
D
9.8 N vertically downwards
Answer
0.49 N vertically downwards
Explanation
Solution
Given, m=0.05kg
We know that, net force acting on a stone,
fg=mg
=0.05×(−9.8)=−0.40N
=0.49N vertically downwards