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Question

Physics Question on laws of motion

A stone of mass 0.05kg0.05 \,kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion ?

A

0.49 N vertically upwards

B

0.49 N vertically downwards

C

0.98 N vertically downwards

D

9.8 N vertically downwards

Answer

0.49 N vertically downwards

Explanation

Solution

Given, m=0.05kgm = 0.05\, kg
We know that, net force acting on a stone,
fg=mgf_{g}=mg
=0.05×(9.8)=0.40N= 0.05 \times (-9.8)=-0.40\,N
=0.49N= 0.49 \,N vertically downwards