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Question: A stone is tied to one end of a spring 50 cm long is whirled in a horizontal circle with a constant ...

A stone is tied to one end of a spring 50 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 10 revolutions in 20 s, what is the magnitude of acceleration of the stone

A

493 cm/sec2

B

720 cm/sec2

C

860 cm/sec2

D

990 cm/sec2

Answer

493 cm/sec2

Explanation

Solution

Time period =Total timeNo. of revolution=2010=2sec= \frac{\text{Total time}}{\text{No. of revolution}} = \frac{20}{10} = 2sec

ac=4π2T2.r=4π2(2)2×(1/2)⥂⥂m/s2=4.93m/s2\therefore a_{c} = \frac{4\pi^{2}}{T^{2}}.r = \frac{4\pi^{2}}{(2)^{2}} \times (1/2) ⥂ ⥂ m/s^{2} = 4.93m/s^{2}

=493cm/s2= 493cm/s^{2}