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Physics Question on Motion in a straight line

A stone is projected vertically up from the ground With velocity 40ms−140 ms^{-1} The interval of time between the two instants at which the stone is at a height of 60 m above the ground is (g=10ms−2)(g = 10 ms^{-2})

A

4 s

B

6 s

C

8 s

D

12s

Answer

4 s

Explanation

Solution

hint : possible time intervals at which stone is at height h t=u−u2−2ghgt = \frac{u - \sqrt{u^2 - 2gh}}{g}