Question
Question: A steel wire of uniform cross-section of 1 m<sup>2</sup> is heated to 70°C and stretched by tying it...
A steel wire of uniform cross-section of 1 m2 is heated to 70°C and stretched by tying its two ends rigidly. What is the change in the tension of the wire when the temperature falls from 70°C to 35°C? Coefficient of linear expansion of steel is 1.1 10-5 /°C and Young’s modulus is 2.01011N/m2.
A
250N
B
116N
C
77N
D
28N
Answer
77N
Explanation
Solution
The tension produced in a stretched wire due to fall in temperature by ∆t is.
F = YA α∆t
Where Y and α are the Young’s modulus and coefficient of linear expansion of the material of the wire and A is the cross-sectional area.
Here Y = 2.01011N/m2
A = 1.0 mm2 = 1.010-6m2
α = 1.110-5/0C
∆t = (70 – 35) = 350C
∴ F = 2.01011 (1.0 10-6) (1.110-6) 35 = 77N