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Question: A steel wire of uniform cross-section of 1 m<sup>2</sup> is heated to 70°C and stretched by tying it...

A steel wire of uniform cross-section of 1 m2 is heated to 70°C and stretched by tying its two ends rigidly. What is the change in the tension of the wire when the temperature falls from 70°C to 35°C? Coefficient of linear expansion of steel is 1.1 10-5 /°C and Young’s modulus is 2.01011N/m2.

A

250N

B

116N

C

77N

D

28N

Answer

77N

Explanation

Solution

The tension produced in a stretched wire due to fall in temperature by ∆t is.

F = YA α∆t

Where Y and α are the Young’s modulus and coefficient of linear expansion of the material of the wire and A is the cross-sectional area.

Here Y = 2.01011N/m2

A = 1.0 mm2 = 1.010-6m2

α = 1.110-5/0C

∆t = (70 – 35) = 350C

∴ F = 2.01011 (1.0 10-6) (1.110-6) 35 = 77N