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Question

Question: A steel wire of lm long and <img src="https://cdn.pureessence.tech/canvas_258.png?top_left_x=876&top...

A steel wire of lm long and cross section area is hang from rigid end. When weight of 1kg is hung from it then change in length will be (given

A

0.5 mm

B

0.25 mm

C

0.05 mm

D

5 mm

Answer

0.05 mm

Explanation

Solution

l=MgLYA=1×10×12×1011×106=0.05 mml = \frac { M g L } { Y A } = \frac { 1 \times 10 \times 1 } { 2 \times 10 ^ { 11 } \times 10 ^ { - 6 } } = 0.05 \mathrm {~mm}