Solveeit Logo

Question

Physics Question on mechanical properties of solids

A steel wire of 1m1\, m long and 1mm21\, mm^2 cross section area is hanged from rigid end when weight of 1kg1 \,kg is hung from it then change in length will be (for wire Youngs coefficient Y=2×1011N/m2Y=2\times 10^{11}\,N/m^{2} ):

A

0.5 mm

B

0.25 mm

C

0.05 mm

D

5 mm

Answer

0.05 mm

Explanation

Solution

Young's coefficient of elasticity Y=mgLπr2ΔLY=\frac{m g L}{\pi r^{2} \Delta L} substituting the values we get ΔL=0.05mm\Delta L=0.05 \,mm