Question

A steel wire $0.5\, m$ long has a total mass $kg$ and stretched with a tension of $800\, N$. The frequency with which it vibrates in its fundamental note will be :

• A. 4 Hz
• B. 2 Hz
• C. 200 Hz
• D. 160 Hz

Answer 1

Answer: (C)

200 Hz

Answer 2

Mass per unit length
$m=\frac{M}{L}=\frac{0.01}{0.5} kg / m$
Fundamental frequency is
$n=\frac{1}{2 L} \sqrt{\frac{T}{m}}$
$=\frac{1}{2 \times 0.5} \sqrt{\frac{800 \times 0.5}{0.01}}$
$=200 \,Hz$