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Question: A steam of water flowing horizontally with a speed of \(20ms^{- 1}\)gushes out of a tube of cross-se...

A steam of water flowing horizontally with a speed of 20ms120ms^{- 1}gushes out of a tube of cross-sectional area 103m210^{- 3}m^{2}, and hits at a vertical wall nearby. What is the force exerted on the wall by the impact of water?

A

125 N

B

625 N

C

-650 N

D

-1125 N

Answer

625 N

Explanation

Solution

Here, u=25ms1,v=0,t=1,A=103m2u = 25ms^{- 1},v = 0,t = 1,A = 10^{- 3}m^{2}

Density of water ρ=1000kgm3\rho = 1000kgm^{- 3}

Mass of water gushed out per second,

m = volume×densitytime=area×distance×densitytime\frac{volume \times density}{time} = \frac{area \times dis\tan ce \times density}{time}

=Area×velocity×density= Area \times velocity \times density

=Avρ=103×25×1000=25kg= Av\rho = 10^{- 3} \times 25 \times 1000 = 25kg

Force exerted on the wall by the impact of water

F=ma=m(vut)=25×(21)=625NF = ma = m\left( \frac{v - u}{t} \right) = 25 \times \left( \frac{- 2}{1} \right) = 625N

F=F=625NF' = - F = 625N