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Question

Question: A statue 1.46 m tall stands on the top of a pedestal. From a point on the ground, the angle of eleva...

A statue 1.46 m tall stands on the top of a pedestal. From a point on the ground, the angle of elevation of the top of the statue is 60o{60^o} and from the same point the angle of elevation of the top of the pedestal is 45o{45^o}. Find the height of the pedestal [Use3=1.73\sqrt 3 = 1.73]

Explanation

Solution

The problem can be solved by using trigonometry. The formula for the tangent of the angle should be used 2 times. Tangent of an angle is given by, tanθ=PB\tan \theta = \dfrac{P}{B}, where P = perpendicular and B = base of the right triangle.

Complete step-by-step answer:
The figure according to the condition given in the question is as follows,

In right triangle, DBC right angled at C
tan45o=PB=hBC\tan {45^o} = \dfrac{P}{B} = \dfrac{h}{{BC}}
The value of tan45o=1\tan {45^o} = 1
hBC=1 h=BC......(1)  \Rightarrow \dfrac{h}{{BC}} = 1 \\\ h = BC......(1) \\\

In right triangle, ABC right angled at C
tan60o=PB tan60o=ACBC tan60o=h+1.46BC  \tan {60^o} = \dfrac{P}{B} \\\ \tan {60^o} = \dfrac{{AC}}{{BC}} \\\ \tan {60^o} = \dfrac{{h + 1.46}}{{BC}} \\\

The value of tan60o=3\tan {60^o} = \sqrt 3
h+1.46BC=3\Rightarrow \dfrac{{h + 1.46}}{{BC}} = \sqrt 3
h+1.46h=3......(2)\dfrac{{h + 1.46}}{h} = \sqrt 3 ......(2)

Substitute h = BC in equation (2)
h+1.46=h3......(3)h + 1.46 = h\sqrt 3 ......(3)

The value of 3=1.73\sqrt 3 = 1.73 as per the question, substitute it in equation (3)
h+1.46=1.73h 1.73hh=1.46 0.73h=1.46 h=1.460.73 h=2  h + 1.46 = 1.73h \\\ 1.73h - h = 1.46 \\\ 0.73h = 1.46 \\\ h = \dfrac{{1.46}}{{0.73}} \\\ h = 2 \\\
Hence, the height of the pedestal is, h=2h = 2 m.

Note: The figure should be drawn very carefully and the angle should be marked appropriately.
The value of the tangent of the angle should be remembered.