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Question: A stationary wheel starts rotating about its own axis at a constant angular acceleration. If the whe...

A stationary wheel starts rotating about its own axis at a constant angular acceleration. If the wheel completes 5050 rotations in the first 2s2s, then the number of rotations made by it in the next 2s2s is:
A.50 B.100 C.125 D.150 \begin{aligned} & A.50 \\\ & B.100 \\\ & C.125 \\\ & D.150 \\\ \end{aligned}

Explanation

Solution

The problem needs to be solved by using the formula for angular displacement of a particle having uniform angular acceleration. So first, we need to find the total angular displacement in the said 2s2s. Then we have to evaluate the number of rotations for that amount of angular displacement.
Formula used: θ=w1t+12αt2\theta ={{w}_{1}}t+\dfrac{1}{2}\alpha {{t}^{2}} , ω2=ω1+αt{{\omega }_{2}}={{\omega }_{1}}+\alpha t ,θ=2πn\theta =2\pi n

Complete answer:
The angular displacement of a particle having initial angular velocity ω1{{\omega }_{1}} ,uniform angular acceleration α\alpha in time t is given by
θ=w1t+12αt2\theta ={{w}_{1}}t+\dfrac{1}{2}\alpha {{t}^{2}} -----(1)(1) , also the final velocity after time t is given by ω2=ω1+αt{{\omega }_{2}}={{\omega }_{1}}+\alpha t----(2)(2)
Now here, the wheel completes 5050 rotations in the first2s2s, that means the total angular displacement in radian is θ=2π×50rad=100πrad.\theta =2\pi \times 50rad=100\pi rad. Now putting the values of different quantities in(1)(1) we get
100π=0×2+12α×22 orα=50πrads2 \begin{aligned} & 100\pi =0\times 2+\dfrac{1}{2}\alpha \times {{2}^{2}} \\\ & or\alpha =50\pi rad{{s}^{-2}} \\\ \end{aligned}
Now using the equation(2)(2) we get, the velocity acquired by the wheel in the first 2s2s ω2=0+50π×2=100πrads1{{\omega }_{2}}=0+50\pi \times 2=100\pi rad{{s}^{-1}} . So to have the angular displacement in the next 2s2s, we again use the equation (1)(1) and we get
θ1=100π×2+1250π×22rad orθ1=300πrad \begin{aligned} & {{\theta }_{1}}=100\pi \times 2+\dfrac{1}{2}50\pi \times {{2}^{2}}rad \\\ & or {{\theta }_{1}}=300\pi rad \\\ \end{aligned}
So the number of complete rotations in next 2s2s is given by
300π÷2π=150300\pi \div 2\pi =150 .

So the correct option is D.

Note:
We must convert the total angular displacement in the number of rotations by dividing it by 2π2\pi .
Also for the next 2s2s the initial velocity must be calculated. The formulae can only be applied for particles having uniform angular acceleration, for non uniform accelerations the formulae will not work.