Question

A stationary nitrogen ($^{14}_7N$) nucleus is bombarded with α- particle ($^{4}_2He$) and the following nuclear reaction takes place:

If the kinetic energies of $^4_2$ and $^4_2H$ are 5.314MeV and 4.012MeV, respectively, then the kinetic energy of $^{17}_80$ is MeV. (Rounded off to one decimal place)
(Masses are given in units of 𝑢 = 931.5MeV/c2 )

Answer 1

The correct answer is: 0.4