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Question: A star producing light of wavelength 6000 Å moves away from the earth with a speed of 5 km/sec. Due ...

A star producing light of wavelength 6000 Å moves away from the earth with a speed of 5 km/sec. Due to Doppler effect the shift in wavelength will be (c=3×108m/sec)(c = 3 \times 10^{8}m/\sec).

A

0.1 Å

B

0.05 Å

C

0.2 Å

D

1 Å

Answer

0.1 Å

Explanation

Solution

Doppler’s shift is given by

Δλ=vλc=5000×60003×108=0.1A˚\Delta\lambda = \frac{v\lambda}{c} = \frac{5000 \times 6000}{3 \times 10^{8}} = 0.1Å