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Question: A standing wave is formed by the superposition of two waves travelling in opposite directions. The t...

A standing wave is formed by the superposition of two waves travelling in opposite directions. The transverse displacement is given by
y(x,t)=0.5sin(5π4x)cos(200πt)y\left( {x,t} \right) = 0.5\sin \left( {\dfrac{{5\pi }}{4}x} \right)\cos \left( {200\pi t} \right)
What is the speed of the travelling wave moving in the positive xx direction?
(xx and tt are in meter and second, respectively)
(A) 120m/s120m/s
(B) 180m/s180m/s
(C) 90m/s90m/s
(D) 160m/s160m/s

Explanation

Solution

First compare the equation given in the question with the general standing wave equation generated due to superposition of two waves travelling in opposite directions. We can get the value of angular frequency and propagation constant from here. Then using these two values, calculate the velocity of the wave.
Formulas used:
v=ωkv = \dfrac{\omega }{k} where vv is the velocity of the wave, wwis its angular frequency and kk is its propagation constant.

Complete step by step answer
Standing or stationary waves can be generated in two ways:
1. By moving the medium in a direction opposite to the wave.
2. By the superposition of two waves with equal frequency travelling in opposite directions.
In this question, the standing wave is generated due to the superposition of two waves.
Let us consider two waves travelling in positive xx direction and negative xx direction represented by the equations
y1=asin(kxωt){y_1} = a\sin \left( {kx - \omega t} \right) and y2=asin(kx+ωt){y_2} = a\sin \left( {kx + \omega t} \right)
Where aa is the amplitude of the waves, kkis the propagation constant and ww is the angular velocity.
By the principle of superposition the resultant standing wave is given by,
y=y1+y2y = {y_1} + {y_2}
y=a[sin(kxωt)+sin(kx+ωt)] y=a[sinkxcosωtcoskxsinωt+sinkxcosωt+coskxsinωt] y=2asinkxcosωt y=Asinkxcosωt  \Rightarrow y = a\left[ {\sin \left( {kx - \omega t} \right) + \sin \left( {kx + \omega t} \right)} \right] \\\ \Rightarrow y = a\left[ {\sin kx\cos \omega t - \cos kx\sin \omega t + \sin kx\cos \omega t + \cos kx\sin \omega t} \right] \\\ \Rightarrow y = 2a\sin kx\cos \omega t \\\ \Rightarrow y = A\sin kx\cos \omega t \\\
Comparing this equation with the equation given in the question we have,
k=5π4k = \dfrac{{5\pi }}{4} and ω=200π\omega = 200\pi
Now velocity of a wave is given by the formula, v=ωkv = \dfrac{\omega }{k}
So, v=200π5π4=200π×45π=160m/sv = \dfrac{{200\pi }}{{\dfrac{{5\pi }}{4}}} = \dfrac{{200\pi \times 4}}{{5\pi }} = 160m/s
Therefore, the speed of the travelling wave moving in positive xx direction is 160m/s160m/s

So, the correct option is D.

Note: An example of standing wave formation is in the open ocean formed by waves with the same wave period moving in opposite directions. These may form near storm centres, or from reflection of a swell at the shore.