Solveeit Logo

Question

Question: A staircase contains three steps each 10cm high and 20cm wide. What should be the minimum horizontal...

A staircase contains three steps each 10cm high and 20cm wide. What should be the minimum horizontal velocity of a ball rolling off the uppermost plane so as to hit directly the lowest plane?
A)42ms1 B)2ms1 C)24ms1 D)2.4ms1  A)42m{s^{ - 1}} \\\ B)2m{s^{ - 1}} \\\ C)24m{s^{ - 1}} \\\ D)2.4m{s^{ - 1}} \\\

Explanation

Solution

In order to solve this question, firstly we will convert the given height and width in centimeter to meter. Then we will apply the equation of motion i.e.h=ut+12gt2h = ut + \dfrac{1}{2}g{t^2}to find the minimum horizontal velocity required to hit the lowest floor.

Formula used:
h=ut+12gt2h = ut + \dfrac{1}{2}g{t^2}

Complete step by step answer:

Here we are given that-
Height of each step = 10cm
Width of each step = 20cm
The ball will need to clear point B to hit the lowest plane directly.
A horizontal distance equal to 40 cm will move the ball from A to B.
Converting horizontal distance between cm and m,
We 're getting 0.4 m
And the vertical distance is 20 cm.
Converting vertical distance between cm and m,
We 're having -0.2 m
let t be the time taken to reach point B.
In this time, vertical motion under the gravity has data-
U = 0, h = 0,
Using the equation of h, where h is the distance a projectile has fallen after time (t), assuming a starting velocity of zero.
This means,h=ut+12gt2h = ut + \dfrac{1}{2}g{t^2}
Here, h = 0.2
u = 0 (vertical motion)
g = 9.8,
Substituting these values,
We get-
0.2=0+12(9.8)t20.2 = 0 + \dfrac{1}{2}\left( {9.8} \right){t^2}
Or t2=0.49.8{t^2} = \dfrac{{0.4}}{{9.8}}
Or t2=0.04{t^2} = 0.04
t=0.2\therefore t = 0.2
Let v be the ball's horizontal speed,
Then the horizontal distance traveled by the ball = 0.2v
To be explicit on point B, it must be at least = 0.4,
So the minimum velocity required to hit the lowest floor is 0.2v = 0.4
v=2ms1\Rightarrow v = 2m{s^{ - 1}}
Therefore, the minimum velocity required to hit the lowest floor, v=2ms1v = 2m{s^{ - 1}}.

So, the correct answer is “Option B”.

Note:
In order to solve this question, one must know about the equation of motion. In physics, it is defined as the equation that explains the behaviour of a physical system with regards to motion as a function of time. By using this basic approach we can solve such types of questions.