Question

A square shaped coil of area $70\, cm ^2$ having $600$ turns rotates in a magnetic field of $04$ wbm $^{-2}$, about an axis which is parallel to one of the side of the coil and perpendicular to the direction of field If the coil completes $500$ revolution in a minute, the instantaneous emf when the plane of the coil is inclined at $60^{\circ}$ with the field, will be ___ V. (Take $\pi = \frac{22}{7}$)

Answer 1

The correct answer is 44.
N=600,A=70×10−4m2,B=0.4T
ω=60500×2π​=6100π​rad/s
E=NABωsinωt
ωt is angle b/wA&B
=600×70×10−4×0.4×6100π​×21​
=44V