Question

A square loop of side a is rotating about its diagonal with angular velocity ω in a perpendicular magnetic field as shown in the figure. If the number of turns in it is 10 then the magnetic flux linked with the loop at any instant will be

• A. 10 Ba²cosω t
• B. 10 Ba
• C. 10 Ba²
• D. 20 Ba²

Answer 1

Answer: (A)

10 Ba²cosω t

Answer 2

The magnetic flux linked with the loop at any instant of time t is given by φ = BAN cos ω t or φ = 10 Ba² cos ω t

Here N = 10, A = a²