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Question

Physics Question on Electromagnetic induction

A square loop of side 10cm10\, cm and resistance 5Ohm5 \,Ohm is placed vertically in East-West plane. A uniform magnetic field of 11 Tesla is set across the plane in North-East direction. The magnetic field becomes Zero in 700700 ms at a steady rate. The magnitude of induced emfemf during this interval is

A

1mV1 \,mV

B

10mV10 \,mV

C

100mV100 \,mV

D

1V1 \,V

Answer

10mV10 \,mV

Explanation

Solution

Side of square loop =10cm=0.1m=10\,cm=0.1\,m
Area of square loop, A=0.01m2A=0.01\,m^{2}
Magnetic field of loop =1T=1\,T
The square loop is placed vertically in the east-west plane and the magnetic field is applied along north-east direction. So angle between area vector and magnetic field is, θ=45\theta=45^{\circ}.
The flux through the loop, ϕ=ABcosθ\phi=AB\,cos\,\theta
=(0.01)(1)cos45=(0.01) (1) \, cos\,45^{\circ}
=0.007=7×103Wb=0.007 =7 \times 10^{-3}\,Wb
The magnetic field is reduced to zero in time 0.7sec0.7\,sec
So,induced emf is, e=dϕdte=\frac{d\phi}{dt}
=7×1030.7=\frac{7\times10^{-3}}{0.7}
1100V\frac{1}{100}V
=10mV=10\,mV