Question

A square loop of area $25\ cm^2$ has a resistance of $10\ Ω$. The loop is placed in uniform magnetic field of magnitude $40.0 \ T$. The plane of loop is perpendicular to the magnetic field. The work done in pulling the loop out of the magnetic field slowly and uniformly in $1.0$ sec, will be

• A. $1.0×10^{-3} J$
• B. $2.5×10^{−3} J$
• C. $5×10^{−3} J$
• D. $1.0×10^{−4} J$

Answer 1

Answer: (A)

$1.0×10^{-3} J$

Answer 2

The correct option is (A): $1.0×10^{−3} J$