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Question

Physics Question on Current electricity

A square loop, carrying a steady current II, is placed in horizontal plane near a long straight conductor carrying a steady current I1I_{1} at a distance dd from the conductor as shown in figure. The loop will experience

A

a net repulsive force away from the conductor

B

a net torque acting upward perpencicular to the horizontal plane

C

a net torque acting downward normal to the horizontal plane

D

a net attractive force towards the conductor

Answer

a net attractive force towards the conductor

Explanation

Solution

F2=F4F_{2} = - F_{4}
F1=μ0I1Il2πdlF_{1} = \frac{\mu_{0}\,I_{1} \,Il}{2 \pi dl}
F2=μ0I1Il2π(d+l)F_{2} = \frac{\mu_{0} \,I_{1}\,Il}{2\pi\left(d + l\right)}
F1>F3F_{1} > F_{3}
Fnet=F1F3F_{\text{net}} = F_{1} - F_{3}
So, wire attract loop .