Question

A square is inscribed in a circle x² + y² – 2x + 4y + 3 = 0. Its sides are parallel to the coordinate axes. Then one vertex of the square is

• A. (1+$\sqrt{2}$, –2)
• B. (1 –$\sqrt{2}$, –2)
• C. (1, – 2 +$\sqrt{2}$)
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

Centre є (1, –2), radius =$\sqrt{2}$

So x coordinate of any of the vertices cannot be 1 and y cannot be –2.