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Question: A square frame with side **a** as shown in Fig. is moved with a velocity v from a long straight wire...

A square frame with side a as shown in Fig. is moved with a velocity v from a long straight wire carrying current I. Initial separation between straight long wire and square frame is x. Find the emf induced in the frame as a function of distance x.

A

μ0Ia2v2πx(x+a)\frac{\mu_{0}Ia^{2}v}{2\pi x(x + a)}

B

μ0Iaxv2πx(x+a)\frac{\mu_{0}Iaxv}{2\pi x(x + a)}

C

μ0Ia2v4πx(x+a)\frac{\mu_{0}Ia^{2}v}{4\pi x(x + a)}

D

Zero

Answer

μ0Ia2v2πx(x+a)\frac{\mu_{0}Ia^{2}v}{2\pi x(x + a)}

Explanation

Solution

e1 =μ0Iav2πx\frac{\mu_{0}Iav}{2\pi x}

and e2 =μ0Iav2π(x+a)\frac{\mu_{0}Iav}{2\pi(x + a)}

enet = e1 – e2

=[1x1x+a]\left\lbrack \frac{1}{x} - \frac{1}{x + a} \right\rbrack

=μ0Ia2v2πx(x+a)\frac{\mu_{0}Ia^{2}v}{2\pi x(x + a)}