Question
Question: A square coil of 10<sup>–2</sup>m<sup>2</sup> area is placed perpendicular to a uniform magnetic fie...
A square coil of 10–2m2 area is placed perpendicular to a uniform magnetic field of intensity 103wb/m2. The magnetic flux through the coil is
A
10 weber
B
10–5weber
C
105weber
D
100 weber
Answer
10 weber
Explanation
Solution
By using φ = BA cosθ ; here θ = 00
∴ φ = BA = 103 × 10–2 = 10 weber