Question

A square aluminium (shear modulus is 25 × 109 Nm-2) slab of side 60 cm and thickness 15 cm is subjected to a shearing force (on its narrow face) of 18.0 × 104 N. The lower edge is riveted to the floor. The displacement of the upper edge is ______μm.

Answer 1

The correct answer is 48

Fig.

$Y=\frac{FI}{AΔI}$
$ΔI=\frac{Fl}{YA}$
$=\frac{18×10^4×60×10^{−2}}{25×10^{9}×60×15×10^{−4}}$
$=48×10^{−6} m$