Question

A spring of force constant k is cut into two pieces such that one pieces is double the length of the other. Then the long piece will have a force constant of

• A. $2/3k$
• B. $3/2k$
• C. $3k$
• D. $6k$

Answer 1

Answer: (B)

$3/2k$

Answer 2

If $l_{1} = nl_{2}$ then $k_{1} = \frac{(n + 1)k}{n} = \frac{3}{2}k$ [As n = 2]