A spring of force constant (k) is cut integralo two pieces s... | Physics | SolveeIt | Solveeit

Today, August 18

Question

A spring of force constant $k$ is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of

A

$\frac{2}{3}$

B

$\frac{3}{2}$

C

3k

D

6k

Answer

$\frac{3}{2}$

Explanation

Solution

$l_1 = 2l_2 \, \, \, \, \therefore \, \, \, l_1 =\frac{2}{3} l$
$\therefore \, \, \, \, \, \, \, \, \, \, k_1 =\frac{3}{2}k$
Force constant $k \propto \frac{1}{length of spring}$