Solveeit Logo
Login

Question

Question: A spring of force constant 800 N/m has an extension of 5cm. The work done in extending it from 5cm t...

A spring of force constant 800 N/m has an extension of 5cm. The work done in extending it from 5cm to 15 cm is

A

16 J

B

8 J

C

32 J

D

24 J

Answer

8 J

Explanation

Solution

W=12k(x22−x12)=12×800×(152−52)×10−4W = \frac { 1 } { 2 } k \left( x _ { 2 } ^ { 2 } - x _ { 1 } ^ { 2 } \right) = \frac { 1 } { 2 } \times 800 \times \left( 15 ^ { 2 } - 5 ^ { 2 } \right) \times 10 ^ { - 4 }