Question

A spring is stretched by 0.20 m, when a mass of 0.50 kg is suspended. When a mass of 0.25 kg is suspended, then its period of oscillation will be $\left( g = 10 m / s ^ { 2 } \right)$

• A. 0.328 sec
• B. 0.628 sec
• C. 0.137 sec
• D. 1.00 sec

Answer 1

Answer: (B)

0.628 sec

Answer 2

Force constant

$k = \frac { F } { x } = \frac { 0.5 \times 10 } { 0.2 } = 25 \mathrm {~N} / \mathrm { m }$

Now$T = 2 \pi \sqrt { \frac { m } { k } } = 2 \pi \sqrt { \frac { 0.25 } { 25 } } = 0.628$sec