Question
Question: A spot light S moves in a horizontal plane with a constant angular velocity of \[0.1rad/s\]. The spo...
A spot light S moves in a horizontal plane with a constant angular velocity of 0.1rad/s. The spot light P moves along the wall at a distance 3m. When θ=45∘, the velocity of spot P is?
Solution
The rotating spot light has an angular velocity and linear velocity. These two velocities are proportional to each other. Their relationship can be expressed in terms of distance, and angle between the center and angle of rotation. The angle, distance from spotlight to wall and angular velocity of spotlight are given in the question. We can derive the result from the formula for linear velocity.
Formula used:
v=sin2θωr
r=cosθd
Complete answer:
Here, a spot light S is moving horizontally along the wall with an angular velocity of 0.1rad/s. Distance to the wall is 3m. It makes an angle θ=45∘ at a point.
Linear velocity of rotating object is given by,
v=sin2θωr ---------- 1
Where,
ω is the angular velocity
r is the distance from the center
d is the distance from the spotlight to wall,
We have,
r=cosθd
Given,
d=3m
θ=45∘
Then, the distance from the spot of the light from the center at an angle 45∘ is
r=cosθd=cos453=32
r=32
Given,
ω=0.1grad/s
Substitute the values of ω, r and θ in equation 1. We get,
v=sin450.1(32)=0.6m/s
Therefore, answer is v = 0.6m/s
Additional Information:
The rate of change of angular displacement is known as the angular velocity. It has the unit in rad/s. When objects rotate about some axis, each point in the object follows a circular arc. Every point on the rotating object has the same angular velocity. The tangential velocity of each point is proportional to its distance from the axis of rotation.
Note:
The expression, v=ω×r is valid only if ω and r are in the same plane. A unit circle has radius as 1 unit. Hence, in this case linear velocity and angular velocity of an object is the same.