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Question

Physics Question on Gravitation

A spherical planet has a mass MpM_p and diameter DpD_p. A particle of mass mm falling freely near the surface of this planet will experience an acceleration due to gravity, equal to

A

4GMpDp2\frac {4GM_p}{D_p^2}

B

GMpmDp2\frac {GM_pm}{D_p^2}

C

GMpDp\frac {GM_p}{D_p}

D

4GMpmDp2\frac {4GM_pm}{D_p^2}

Answer

4GMpDp2\frac {4GM_p}{D_p^2}

Explanation

Solution

g=GMpRp2g =\frac{ GM _{ p }}{ R _{ p }{ }^{2}} where Rp=Dp/2R _{ p }= D _{ p } / 2