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Question: A spherical drop of water has radius 1 mm If surface tension of water is \(70 \times 10 ^ { - 3 }\)N...

A spherical drop of water has radius 1 mm If surface tension of water is 70×10−370 \times 10 ^ { - 3 }N/m difference of pressures between inside and out side of the spherical drop is

A

B

C

D

Zero

Answer

Explanation

Solution

ΔP=2TR=2×70×10−31×10−3=140 N/m2\Delta P = \frac { 2 T } { R } = \frac { 2 \times 70 \times 10 ^ { - 3 } } { 1 \times 10 ^ { - 3 } } = 140 \mathrm {~N} / \mathrm { m } ^ { 2 }