Question
Physics Question on Electric charges and fields
A spherical conducting shell of inner radius r1 and outer radius r2 has a charge Q. A charge −q is placed at the centre of the shell. The surface charge density on the inner and outer surfaces of the shell will be
A
4πr21q and 4πr22Q
B
4πr21−q and 4πr22Q+q
C
4πr12q and 4πr22Q−q
D
0 and 4πr22Q−q
Answer
4πr12q and 4πr22Q−q
Explanation
Solution
Surface charge density
(σ)= Surface area Charge
∴σinner =4πr12−q
and σouter =4πr22Q−q